Events D, E, F and G are independent events, and P(D) = 0.4, P(E) = .6, P(F) = 0.3, and P(G) = 0.2. Find the?

Events D, E, F and G are independent events, and P(D) = 0.4, P(E) = .6, P(F) = 0.3, and P(G) = 0.2. Find the probability of P(D and F and G).

Events D, E, F and G are independent events, and P(D) = 0.4, P(E) = .6, P(F) = 0.3, and P(G) = 0.2. Find the?
of all occuring .2
Reply:Given events D, E, F, and G are independent i.e the probability of occurance of each event is not depends upon the probability of occurance of other event.





Given P(D) = 0.4


P(E) = 0.6


P(F) = 0.3


P(G) = 0.2





P (D and F and G) = P(D) x P(F) x P(G)


= 0.4 x 0.3 x 0.2


= 0.024





Therefore P (D and F and G) = 0.024








For more detailes and better understnding:





http://www.futureaccountant.com/probabil...





http://www.schoolingkids.com/probability...
Reply:P(D and F and G) = 0.4 * 0.3 * 0.2 = 0.024
Reply:If the events are independent, the probability of


all will happen is the product of their probability.


P(D and F and G)= 0.4 * 0.3 * 0.2


The 'and' is the common part of the groups,


the 'or' is the sum of all the grops.


But beware: when you count 'or', you have to substract


the common parts, becouse you counted them more than


one time.